kinematics_AP Physics 1
知识点

例题

解题过程
GIVEN:
v0=20m/s (upward)
vf=0m/s
FIND: t=?
SOLVE:
by formula: vf=v0+at
0=20+9.8t
t=2.04s
GIVEN:
v0=150m/s
vf=0m/s (stop)
a=-3m/s^2
FIND: delta x=?
SOLVE:
by formula: vf^2=v0^2+2a delta x
0^2=150^2+2(-3)delta x
delta x= 3750 m
GIVEN:
v0=-25m/s
t=2s
FIND: vf=?
SOLVE:
by formula: vf=v0+at
vf=-25+(-9.8)*2=-44.6m/s
GIVEN:
v0=0m/s (accelerate from rest)
a=25m/s^2 (upward)
t=5s
FIND:
x
SOLVE:
x=
x1+
x2
Before 5 s of accelerating
by formula:
x=v0*t+(1/2)a*t^2
x1=v0*t+1/2at^2=0+(1/2)*25*5^2=312.5 m
v0'=v0+at=0+25*5=125 (continue to accelerate upward)
to FIND: t
vf=0 ( no accelerat)
vf=v0+at
0=125+(-9.8)t
t=12.76 s
After 5 s of accelerating
x2=v0*t+1/2at^2=125*12.76+(1/2)(-9.8)(12.76^2)=797.2 m
x=
x1+
x2=312.5+797.2=1109.7 m