LeetCode 2558. Take Gifts From the Richest Pile

You are given an integer array gifts denoting the number of gifts in various piles. Every second, you do the following:

• Choose the pile with the maximum number of gifts.

• If there is more than one pile with the maximum number of gifts, choose any.

• Leave behind the floor of the square root of the number of gifts in the pile. Take the rest of the gifts.

Return the number of gifts remaining after k seconds.

Example 1:

Input: gifts = [25,64,9,4,100], k = 4Output: 29Explanation: The gifts are taken in the following way: - In the first second, the last pile is chosen and 10 gifts are left behind. - Then the second pile is chosen and 8 gifts are left behind. - After that the first pile is chosen and 5 gifts are left behind. - Finally, the last pile is chosen again and 3 gifts are left behind. The final remaining gifts are [5,8,9,4,3], so the total number of gifts remaining is 29.

Example 2:

Input: gifts = [1,1,1,1], k = 4Output: 4Explanation: In this case, regardless which pile you choose, you have to leave behind 1 gift in each pile. That is, you can't take any pile with you. So, the total gifts remaining are 4.

Constraints:

• 1 <= gifts.length <= 103

• 1 <= gifts[i] <= 109

• 1 <= k <= 103

Accepted

20,467

Submissions

31,124

1：写一个函数返回最大值的index；

2：每次对最大值进行开平方根；

3：最后求数组的和，返回即可；

用的是普通的遍历，easy题目了；

Runtime: 8 ms, faster than 27.13% of Java online submissions for Take Gifts From the Richest Pile.

Memory Usage: 41.4 MB, less than 99.19% of Java online submissions for Take Gifts From the Richest Pile.