欢迎光临散文网 会员登陆 & 注册

LeetCode 2037. Minimum Number of Moves to Seat Everyone

2023-06-03 13:57 作者:您是打尖儿还是住店呢  | 我要投稿

There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the ith seat. You are also given the array students of length n, where students[j] is the position of the jth student.

You may perform the following move any number of times:

  • Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1)

Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat.

Note that there may be multiple seats or students in the same position at the beginning.

 

Example 1:

Input: seats = [3,1,5], students = [2,7,4]

Output: 4

Explanation: 

The students are moved as follows: - The first student is moved from from position 2 to position 1 using 1 move. - The second student is moved from from position 7 to position 5 using 2 moves. - The third student is moved from from position 4 to position 3 using 1 move. In total, 1 + 2 + 1 = 4 moves were used.

Example 2:

Input: seats = [4,1,5,9], students = [1,3,2,6]

Output: 7

Explanation: 

The students are moved as follows: - The first student is not moved. - The second student is moved from from position 3 to position 4 using 1 move. - The third student is moved from from position 2 to position 5 using 3 moves. - The fourth student is moved from from position 6 to position 9 using 3 moves. In total, 0 + 1 + 3 + 3 = 7 moves were used.

Example 3:

Input: seats = [2,2,6,6], students = [1,3,2,6]

Output: 4

Explanation:

Note that there are two seats at position 2 and two seats at position 6. The students are moved as follows: - The first student is moved from from position 1 to position 2 using 1 move. - The second student is moved from from position 3 to position 6 using 3 moves. - The third student is not moved. - The fourth student is not moved. In total, 1 + 3 + 0 + 0 = 4 moves were used.

 

Constraints:

  • n == seats.length == students.length

  • 1 <= n <= 100

  • 1 <= seats[i], students[j] <= 100

学生跟位置依次排序,然后返回位置跟学生的差值的绝对值,返回即可;

下面是代码;

Runtime: 2 ms, faster than 98.41% of Java online submissions for Minimum Number of Moves to Seat Everyone.

Memory Usage: 43.3 MB, less than 17.17% of Java online submissions for Minimum Number of Moves to Seat Everyone.


LeetCode 2037. Minimum Number of Moves to Seat Everyone的评论 (共 条)

分享到微博请遵守国家法律