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LeetCode 523. Continuous Subarray Sum

2023-04-27 14:40 作者:您是打尖儿还是住店呢  | 我要投稿

Given an integer array nums and an integer k, return true if nums has a good subarray or false otherwise.

A good subarray is a subarray where:

  • its length is at least two, and

  • the sum of the elements of the subarray is a multiple of k.

Note that:

  • A subarray is a contiguous part of the array.

  • An integer x is a multiple of k if there exists an integer n such that x = n * k0 is always a multiple of k.

 

Example 1:

Input: nums = [23,2,4,6,7], k = 6

Output: true

Explanation: [2, 4] is a continuous subarray of size 2 whose elements sum up to 6.

Example 2:

Input: nums = [23,2,6,4,7], k = 6

Output: true

Explanation: [23, 2, 6, 4, 7] is an continuous subarray of size 5 whose elements sum up to 42. 42 is a multiple of 6 because 42 = 7 * 6 and 7 is an integer.

Example 3:

Input: nums = [23,2,6,4,7], k = 13

Output: false

 

Constraints:

  • 1 <= nums.length <= 105

  • 0 <= nums[i] <= 109

  • 0 <= sum(nums[i]) <= 231 - 1

  • 1 <= k <= 231 - 1

  • 每次用map去存储这个余数对应的位置,如果存在i-对应的位置大于1,说明是超过2个的,这时候返回true即可,剩下的情况就是返回false了;

  • 下面是代码:


Runtime: 21 ms, faster than 80.19% of Java online submissions for Continuous Subarray Sum.

Memory Usage: 51.7 MB, less than 62.16% of Java online submissions for Continuous Subarray Sum.


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