LeetCode 523. Continuous Subarray Sum
Given an integer array nums and an integer k, return true
if nums
has a good subarray or false
otherwise.
A good subarray is a subarray where:
its length is at least two, and
the sum of the elements of the subarray is a multiple of
k
.
Note that:
A subarray is a contiguous part of the array.
An integer
x
is a multiple ofk
if there exists an integern
such thatx = n * k
.0
is always a multiple ofk
.
Example 1:
Input: nums = [23,2,4,6,7], k = 6
Output: true
Explanation: [2, 4] is a continuous subarray of size 2 whose elements sum up to 6.
Example 2:
Input: nums = [23,2,6,4,7], k = 6
Output: true
Explanation: [23, 2, 6, 4, 7] is an continuous subarray of size 5 whose elements sum up to 42. 42 is a multiple of 6 because 42 = 7 * 6 and 7 is an integer.
Example 3:
Input: nums = [23,2,6,4,7], k = 13
Output: false
Constraints:
1 <= nums.length <= 105
0 <= nums[i] <= 109
0 <= sum(nums[i]) <= 231 - 1
1 <= k <= 231 - 1
每次用map去存储这个余数对应的位置,如果存在i-对应的位置大于1,说明是超过2个的,这时候返回true即可,剩下的情况就是返回false了;
下面是代码:
Runtime: 21 ms, faster than 80.19% of Java online submissions for Continuous Subarray Sum.
Memory Usage: 51.7 MB, less than 62.16% of Java online submissions for Continuous Subarray Sum.