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CCE 到 REG 的映射公式

2023-06-15 11:07 作者:乐吧的数学  | 我要投稿

（录制的视频在：https://www.bilibili.com/video/BV1Ku411e7SX/）

协议 38.211的 g20 版本，第 7.3.2.2 节涉及的公式的说明，其中比较绕的公式如下：

f(x)%20%3D%20(rC%20%2B%20c%20%2B%20n_%7Bshift%7D)%20mod%20(N%5E%7BCORESET%7D_%7BREG%7D%2FL)%20%5C%5C%0A%0Ax%3DcR%20%2B%20r%5C%5C%0A%0Ar%3D0%2C1%2C...%2CR-1%20%5C%5C%0A%0Ac%3D0%2C1%2C...%2CC-1%20%5C%5C%0A%0AC%20%3D%20N%5E%7BCORESET%7D_%7BREG%7D%2F(LR)%20%20%5Ctag%201


公式 (1) 用于对于第 j 个 CCE，找出来构成这个 CCE 的 bundle:

%5C%7Bf(6j%2FL)%2Cf(6j%2FL%2B1)%2C...%2Cf(6j%2FL%2BL-1)%5C%7D%20%20%5Ctag%202



L 是 bundle 的大小， 则 N%5E%7BCORESET%7D_%7BREG%7D%2FL  就是含有多少个 bundle.


R 是  interleave size，可以看成是跳跃多少个 bundle 去取一个 bundle.


那么 C 就是把所有的 bundle 分成了几段。则 C 乘以 R 就是总的 bundle 数量。


(上面这些都是针对 interleave 的，如果不是 interleave，则 bundle size L = 6, f(x) = x，就是按照顺序取 6 个 REG 作为一个 CCE)。




举例：2个 symbols 的情况， N = 24, L=2，则 N/L=24/2=12个bundles. 


若 R = 3, 则 C = N/(LR) = 24/(2*3) = 4.

CCE(0)%20%3D%20%5C%7Bf(6*0%2F2)%2Cf(6*0%2F2%2B1)%2Cf(6*0%2F2%2B2)%5C%7D%20%3D%5C%7Bf(0)%2Cf(1)%2Cf(2)%5C%7D%20%5C%5C%0A%0ACCE(1)%20%3D%20%5C%7Bf(6*1%2F2)%2Cf(6*1%2F2%2B1)%2Cf(6*1%2F2%2B2)%5C%7D%20%3D%5C%7Bf(3)%2Cf(4)%2Cf(5)%5C%7D%20%5C%5C%0A%0ACCE(2)%20%3D%20%5C%7Bf(6*2%2F2)%2Cf(6*2%2F2%2B1)%2Cf(6*2%2F2%2B2)%5C%7D%20%3D%5C%7Bf(6)%2Cf(7)%2Cf(8)%5C%7D%20%5C%5C%0A%0ACCE(3)%20%3D%20%5C%7Bf(6*3%2F2)%2Cf(6*3%2F2%2B1)%2Cf(6*3%2F2%2B2)%5C%7D%20%3D%5C%7Bf(9)%2Cf(10)%2Cf(11)%5C%7D%20%20%5Ctag%203



则：

0%3DcR%2Br%3D0*3%2B0%2C%20c%3D0%2Cr%3D0%2CrC%2Bc%3D0*4%2B0%3D0%20%20%5C%5C%0A%0A1%3DcR%2Br%3D0*3%2B1%2C%20c%3D0%2Cr%3D1%2CrC%2Bc%3D1*4%2B0%3D4%20%20%5C%5C%0A%0A2%3DcR%2Br%3D0*3%2B2%2C%20c%3D0%2Cr%3D2%2CrC%2Bc%3D2*4%2B0%3D8%20%20%5C%5C%0A%5C%5C%20%20%5C%5C%0A%0A3%3DcR%2Br%3D1*3%2B0%2C%20c%3D1%2Cr%3D0%2CrC%2Bc%3D0*4%2B1%3D1%20%20%5C%5C%0A%0A4%3DcR%2Br%3D1*3%2B1%2C%20c%3D1%2Cr%3D1%2CrC%2Bc%3D1*4%2B1%3D5%20%20%5C%5C%0A%0A5%3DcR%2Br%3D1*3%2B2%2C%20c%3D1%2Cr%3D2%2CrC%2Bc%3D2*4%2B1%3D9%20%20%5C%5C%0A%0A%5C%5C%0A%0A6%3DcR%2Br%3D2*3%2B0%2C%20c%3D2%2Cr%3D0%2CrC%2Bc%3D0*4%2B2%3D2%20%20%5C%5C%0A%0A7%3DcR%2Br%3D2*3%2B1%2C%20c%3D2%2Cr%3D1%2CrC%2Bc%3D1*4%2B2%3D6%20%20%5C%5C%0A%0A8%3DcR%2Br%3D2*3%2B2%2C%20c%3D2%2Cr%3D2%2CrC%2Bc%3D2*4%2B2%3D10%20%5C%5C%0A%0A%5C%5C%0A%0A9%3DcR%2Br%3D3*3%2B0%2C%20c%3D3%2Cr%3D0%2CrC%2Bc%3D0*4%2B3%3D3%20%20%5C%5C%0A%0A10%3DcR%2Br%3D3*3%2B1%2C%20c%3D3%2Cr%3D1%2CrC%2Bc%3D1*4%2B3%3D7%20%20%5C%5C%0A%0A11%3DcR%2Br%3D3*3%2B2%2C%20c%3D3%2Cr%3D2%2CrC%2Bc%3D2*4%2B3%3D11%20%20%5C%5C

若 R=6，则 C = N/(LR) = 24/(2*6)=2

0%3DcR%2Br%3D0*6%2B0%2C%20c%3D0%2Cr%3D0%2CrC%2Bc%3D0*2%2B0%3D0%20%20%5C%5C%0A%0A1%3DcR%2Br%3D0*6%2B1%2C%20c%3D0%2Cr%3D1%2CrC%2Bc%3D1*2%2B0%3D2%20%20%5C%5C%0A%0A2%3DcR%2Br%3D0*6%2B2%2C%20c%3D0%2Cr%3D2%2CrC%2Bc%3D2*2%2B0%3D4%20%20%5C%5C%0A%0A%5C%5C%0A%0A3%3DcR%2Br%3D0*6%2B3%2C%20c%3D0%2Cr%3D3%2CrC%2Bc%3D3*2%2B0%3D6%20%20%5C%5C%0A%0A4%3DcR%2Br%3D0*6%2B4%2C%20c%3D0%2Cr%3D4%2CrC%2Bc%3D4*2%2B0%3D8%20%20%5C%5C%0A%0A5%3DcR%2Br%3D0*6%2B5%2C%20c%3D0%2Cr%3D5%2CrC%2Bc%3D5*2%2B0%3D10%20%20%5C%5C%0A%0A%5C%5C%0A%0A6%3DcR%2Br%3D1*6%2B0%2C%20c%3D1%2Cr%3D0%2CrC%2Bc%3D0*2%2B1%3D1%20%20%5C%5C%0A%0A7%3DcR%2Br%3D1*6%2B1%2C%20c%3D1%2Cr%3D1%2CrC%2Bc%3D1*2%2B1%3D3%20%20%5C%5C%0A%0A8%3DcR%2Br%3D1*6%2B2%2C%20c%3D1%2Cr%3D2%2CrC%2Bc%3D2*2%2B1%3D5%20%20%5C%5C%0A%0A%5C%5C%0A%0A9%3DcR%2Br%3D1*6%2B3%2C%20c%3D1%2Cr%3D3%2CrC%2Bc%3D3*2%2B1%3D7%20%20%5C%5C%0A%0A10%3DcR%2Br%3D1*6%2B4%2C%20c%3D1%2Cr%3D4%2CrC%2Bc%3D4*2%2B1%3D9%20%20%5C%5C%0A%0A11%3DcR%2Br%3D1*6%2B5%2C%20c%3D1%2Cr%3D5%2CrC%2Bc%3D5*2%2B1%3D11


若 R=2, 则 C=N/(LR)=24/(2*2)=6

0%3DcR%2Br%3D0*2%2B0%2C%20c%3D0%2Cr%3D0%2CrC%2Bc%3D0*6%2B0%3D0%20%20%5C%5C%0A%0A1%3DcR%2Br%3D0*2%2B1%2C%20c%3D0%2Cr%3D1%2CrC%2Bc%3D1*6%2B0%3D6%20%20%5C%5C%0A%0A2%3DcR%2Br%3D1*2%2B0%2C%20c%3D1%2Cr%3D0%2CrC%2Bc%3D0*6%2B1%3D1%20%20%5C%5C%0A%0A%5C%5C%0A%0A3%3DcR%2Br%3D1*2%2B1%2C%20c%3D1%2Cr%3D1%2CrC%2Bc%3D1*6%2B1%3D7%20%20%5C%5C%0A%0A4%3DcR%2Br%3D2*2%2B0%2C%20c%3D2%2Cr%3D0%2CrC%2Bc%3D0*6%2B2%3D2%20%20%5C%5C%0A%0A5%3DcR%2Br%3D2*2%2B1%2C%20c%3D2%2Cr%3D1%2CrC%2Bc%3D1*6%2B2%3D8%20%20%5C%5C%0A%0A%5C%5C%0A%0A6%3DcR%2Br%3D3*2%2B0%2C%20c%3D3%2Cr%3D0%2CrC%2Bc%3D0*6%2B3%3D3%20%20%5C%5C%0A%0A7%3DcR%2Br%3D3*2%2B1%2C%20c%3D3%2Cr%3D1%2CrC%2Bc%3D1*6%2B3%3D9%20%20%5C%5C%0A%0A8%3DcR%2Br%3D4*2%2B0%2C%20c%3D4%2Cr%3D0%2CrC%2Bc%3D0*6%2B4%3D4%20%20%5C%5C%0A%0A%5C%5C%0A%0A9%3DcR%2Br%3D4*2%2B1%2C%20c%3D4%2Cr%3D1%2CrC%2Bc%3D1*6%2B4%3D10%20%20%5C%5C%0A%0A10%3DcR%2Br%3D5*2%2B0%2C%20c%3D5%2Cr%3D0%2CrC%2Bc%3D0*6%2B5%3D5%20%20%5C%5C%0A%0A11%3DcR%2Br%3D5*2%2B1%2C%20c%3D5%2Cr%3D1%2CrC%2Bc%3D1*6%2B5%3D11%20%20%5C%5C


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CCE 到 REG 的映射公式的评论 (共 条)

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