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对称化改造:缘起(2017北京圆锥曲线)

2022-07-16 00:03 作者:数学老顽童  | 我要投稿

(2017北京理,18)已知抛物线Cy%5E2%3D2px过点P%5Cleft(%201%2C1%20%5Cright)%20,过点%5Cleft(%200%2C%5Cfrac%7B1%7D%7B2%7D%20%5Cright)%20作直线l与抛物线C交于不同的两点MN,过点Mx轴的垂线分别与直线OPON交于点AB,其中O为原点.

(1)求抛物线C的方程,并求其焦点坐标和准线方程;

(2)求证:A为线段BM的中点.

解:(1)由题可知1%5E2%3D2p%5Ccdot%201

解得p%3D%5Cfrac%7B1%7D%7B2%7D

故抛物线C的方程为y%5E2%3Dx

其焦点坐标为%5Cleft(%20%5Cfrac%7B1%7D%7B4%7D%2C0%20%5Cright)%20

准线方程为x%3D-%5Cfrac%7B1%7D%7B4%7D.

(2)先画图

A为线段BM的中点,

y_M%2By_B%3D2y_A,则

%5Cbegin%7Baligned%7D%0A%09k_%7BOM%7D%2Bk_%7BOB%7D%26%3D%5Cfrac%7By_M%7D%7Bx_M%7D%2B%5Cfrac%7By_B%7D%7Bx_B%7D%5C%5C%0A%09%26%3D%5Cfrac%7By_M%7D%7Bx_A%7D%2B%5Cfrac%7By_B%7D%7Bx_A%7D%5C%5C%0A%09%26%3D%5Cfrac%7By_M%2By_B%7D%7Bx_A%7D%5C%5C%0A%09%26%3D%5Cfrac%7B2y_A%7D%7Bx_A%7D%5C%5C%0A%09%26%3D2k_%7BOA%7D%5C%5C%0A%09%26%3D2k_%7BOP%7D%3D2%5C%5C%0A%5Cend%7Baligned%7D

故只需证k_%7BOM%7D%2Bk_%7BOB%7D%3D2即可.

设直线l的方程为mx%2Bny%3D1

因其过%5Cleft(%200%2C%5Cfrac%7B1%7D%7B2%7D%20%5Cright)%20

所以m%5Ccdot0%20%2Bn%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%20%3D1

解得n%3D2

l的方程的为mx%2B2y%3D1

与抛物线C联立,得y%5E2%3Dx%5Cleft(%20mx%2B2y%20%5Cright)%20

整理得y%5E2-2xy-mx%5E2%3D0

各项同除以x%5E2,得

%5Cleft(%20%5Cfrac%7By%7D%7Bx%7D%20%5Cright)%20%5E2-2%5Ccdot%20%5Cfrac%7By%7D%7Bx%7D-m%3D0

k_%7BOM%7D%2Bk_%7BOB%7D%3D%5Cfrac%7By_1%7D%7Bx_1%7D%2B%5Cfrac%7By_2%7D%7Bx_2%7D%3D2

证毕.

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