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[Mechanics] Ballistic Pendulum

2021-08-04 15:21 作者:AoiSTZ23  | 我要投稿

By:Tao Steven Zheng (郑涛)


【Problem】

A bullet of mass m%20 is fired into a stationary block of mass M  at some velocity v_b. The block is attached to a wire (assume massless and infinitely rigid). The bullet-block system swings to a height h.

Part 1: Explain why the conservation of energy cannot be applied before the collision?

Part 2: Determine v_b in terms of m%20, M , and h.

Part 3: Suppose the block is 100 times heavier than the bullet. If the bullet-block system swings to a height of 20 cm, what was the velocity of the bullet? Assume this setup is on Earth.


【Solution】

Part 1

Energy is only conserved in perfectly elastic collisions. Since this collision is inelastic, energy is not conserved prior to collision and during the collision. However, kinetic energy of the bullet-block system is conserved post collision, which is converted to gravitational potential energy.

Part 2

Conservation of momentum (before and during collision).

m%20v_b%20%2B%20M(0)%20%3D%20(m%2BM)v'%20


Conservation of energy (post collision).

%20%5Cfrac%7B1%7D%7B2%7D%20(m%2BM)%20(v')%5E2%20%3D%20(m%2BM)gh


From the conservation of momentum

v'%20%3D%20%5Csqrt%7B2gh%7D


Thus,

v_b%20%3D%20%5Cfrac%7Bm%2BM%7D%7Bm%7D%20%5Csqrt%7B2gh%7D

Part 3


v_b%20%3D%20%5Cfrac%7Bm%2BM%7D%7Bm%7D%20%5Csqrt%7B2gh%7D


%20v_b%20%3D%20%5Cfrac%7Bm%2B100m%7D%7Bm%7D%20%5Csqrt%7B2(9.8)(0.20)%7D


v_b%20%3D%20101%5Csqrt%7B2(9.8)(0.20)%7D%20


v_b%20%3D%20200%20%5C%2C%20m%2Fs

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