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(圆锥曲线)斜率与齐次化

2022-08-21 11:17 作者:因恋相思久  | 我要投稿


已知椭圆C%EF%BC%9A%5Cfrac%7Bx%5E2%20%7D%7Ba%5E2%20%7D%20%2B%5Cfrac%7By%5E2%20%7D%7Bb%5E2%7D%20%3D1%EF%BC%88a%EF%BC%9Eb%EF%BC%9E0%EF%BC%89的短轴长为2%5Csqrt%7B2%7D%20,离心率为%5Cfrac%7B1%7D%7B3%7D%20

(1)求椭圆方程C

(2)设椭圆的左右焦点为F_%7B1%7D%20%EF%BC%8CF_%7B2%7D%20,左右顶点为A,B,点M,N,D位于椭圆互不相交的三点,其中M,D在x轴的上方,若直线MN过焦点F_%7B1%7D%20MN%E2%88%A5F_%7B2%7D%20D,记AM,BD的斜率为k_%7B1%7D%EF%BC%8C%20k_%7B2%7D%20,且满足3k_%7B1%7D%2B2%20k_%7B2%7D%20%3D0,求直线MN方程

(1)由题意得b%3D2%5Csqrt%7B2%7D%20%5Cfrac%7Bc%7D%7Ba%7D%3D%20%5Cfrac%7B1%7D%7B3%7D%20a%5E2%3D%20b%5E2%2B%20c%5E2

联立解得a%3D3%EF%BC%8Cc%3D1

椭圆方程为%5Cfrac%7Bx%5E2%20%7D%7B9%20%7D%20%2B%5Cfrac%7By%5E2%20%7D%7B8%7D%20%3D1

(2)

当直线MN存在时

%E8%AE%BEM%EF%BC%88x_%7B1%7D%20%EF%BC%8Cy_%7B1%7D%20%EF%BC%89%EF%BC%8CN%EF%BC%88x_%7B2%7D%20%EF%BC%8Cy_%7B2%7D%20%EF%BC%89%E7%9B%B4%E7%BA%BF%EF%BC%9An%EF%BC%88x%2B3%EF%BC%89%2Bmy%3D1

因为F_%7B1%7D%20N%E2%88%A5F_%7B2%7D%20D

根据椭圆的对称性知D%EF%BC%88-x_%7B2%7D%20%EF%BC%8C-y_%7B2%7D%20%EF%BC%89

%E6%89%80%E4%BB%A5k_%7B1%7D%20%3D%5Cfrac%7By_%7B1%7D%7D%7B%EF%BC%88x_%7B1%7D%20%2B3%EF%BC%89%7D%20k_%7B2%7D%20%3D%5Cfrac%7By_%7B2%7D%7D%7B%EF%BC%88x_%7B2%7D%2B3%EF%BC%89%20%7D%20

下面进行齐次化

8x%5E2%20%20%2B9y%5E2%20%3D72

8%EF%BC%88x%2B3-3%EF%BC%89%5E2%20%20%2B9y%5E2%20%3D72

8%EF%BC%88x%2B3%EF%BC%89%5E2-48%EF%BC%88x%2B3%EF%BC%89%20%20%2B9y%5E2%20%3D0

8%EF%BC%88x%2B3%EF%BC%89%5E2-48%EF%BC%88x%2B3%EF%BC%89%5B%5Cfrac%7B1%7D%7B2%7D%20%EF%BC%88x%2B3%EF%BC%89%2Bmy%5D%20%20%2B9y%5E2%20%3D0

-16%EF%BC%88x%2B3%EF%BC%89%5E2-48m%EF%BC%88x%2B3%EF%BC%89y%2B9y%5E2%20%3D0

所以-16-48m%EF%BC%88%5Cfrac%7By%7D%7Bx%2B3%7D%20%EF%BC%89%2B9%EF%BC%88%5Cfrac%7By%7D%7Bx%2B3%7D%20%EF%BC%89%5E2%20%20%3D0

k_%7B1%7D%2B%20k_%7B2%7D%20%3D%5Cfrac%7By_%7B1%7D%20%7D%7B%EF%BC%88x_%7B1%7D%20%2B3%EF%BC%89%7D%2B%20%5Cfrac%7By_%7B2%7D%20%7D%7B%EF%BC%88x_%7B2%7D%2B3%20%EF%BC%89%7D%20%3D%5Cfrac%7B16m%7D%7B3%7D%20%E2%91%A0

k_%7B1%7D%20k_%7B2%7D%20%3D%5Cfrac%7By_%7B1%7D%20%20y_%7B2%7D%20%7D%7B%EF%BC%88x_%7B1%7D%2B3%20%EF%BC%89%EF%BC%88x_%7B2%7D%20%2B3%EF%BC%89%7D%20%3D-%5Cfrac%7B16%7D%7B9%7D%20%E2%91%A1

因为3k_%7B1%7D%2B2%20k_%7B2%7D%20%3D0

①③联立得

k_%7B1%7D%3D16m%20%EF%BC%8Ck_%7B2%7D%20%3D%5Cfrac%7B-32m%7D%7B3%7D%20

②④联立得

m%5E2%20%3D%5Cfrac%7B1%7D%7B96%7D%20

解得m_%7B1%7D%3D%5Cfrac%7B%5Csqrt%7B6%7D%20%7D%7B24%7D%20%20%EF%BC%8Cm_%7B2%7D%20%3D-%5Cfrac%7B%5Csqrt%7B6%7D%20%20%7D%7B24%7D%20

直线MN方程为%5Cfrac%7B1%7D%7B2%7D%20%EF%BC%88x%2B1%EF%BC%89%2B%5Cfrac%7B%5Csqrt%7B6%7D%20%7D%7B24%7D%20y%3D0%E6%88%96%5Cfrac%7B1%7D%7B2%7D%20%EF%BC%88x%2B1%EF%BC%89-%5Cfrac%7B%5Csqrt%7B6%7D%20%7D%7B24%7D%20y%3D0

当斜率不存在时

此时M%EF%BC%88-1%EF%BC%8C%5Cfrac%7B8%7D%7B3%7D%20%EF%BC%89D%EF%BC%881%EF%BC%8C%5Cfrac%7B8%7D%7B3%7D%20%EF%BC%89

3k_%7B1%7D%20%2B2k_%7B2%7D%20%3D%5Cfrac%7B8%7D%7B-1-%EF%BC%88-3%EF%BC%89%7D%20%2B%5Cfrac%7B%5Cfrac%7B16%7D%7B3%7D%20%7D%7B1-3%7D%20%3D%5Cfrac%7B4%7D%7B3%7D%20%5Cneq%200

与题目条件矛盾

综上,直线MN方程为%5Cfrac%7B1%7D%7B2%7D%20%EF%BC%88x%2B1%EF%BC%89%2B%5Cfrac%7B%5Csqrt%7B6%7D%20%7D%7B24%7D%20y%3D0%E6%88%96%5Cfrac%7B1%7D%7B2%7D%20%EF%BC%88x%2B1%EF%BC%89-%5Cfrac%7B%5Csqrt%7B6%7D%20%7D%7B24%7D%20y%3D0

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