Can you solve the giant cat army riddle

你能解决巨猫军之谜吗

来源视频

The villainous Dr. Schrödinger has developed a growth ray and intends to create an army of giant cats to terrorize the city. 

Your team of secret agents has tracked him to his underground lab. 

You burst in to find… that it’s a trap!

Dr. Schrödinger has slipped into the next room to activate his device and disabled the control panel on the way out.

邪恶博士薛定谔 发明了一种生长射线，他意图制造一支巨猫军队，造成市民恐慌。

你所在的秘密特工小队跟踪薛定谔博士 来到他的地下实验室。

你们经过深入调查， 却发现这是个陷阱！

薛定谔博士已经到隔壁房间 激活了他的装置，他破坏了撤出路线的控制板。

Fortunately, your teammates are masters of spy-craft. Agent Delta has hacked into the control panel and managed to reactivate some of its functionality. 

Meanwhile, Agent Epsilon has searched through surveillance to find the code for the door: 2, 10, 14. All you have to do is enter those numbers and you’ll be free.

But there’s a problem. 

The control panel has only three buttons: one which adds 5 to the display number, one which adds 7, and one which takes the square root. 

You need to make the display output the numbers 2, 10, and 14, in that order.

It’s okay if it outputs different numbers in between, but there’s no way to reset the display, so once you get to 2, you’ll have to continue on to 10 and 14 from there.

幸运的是， 你的团队成员都是间谍大师。德尔塔特工黑入了控制面板，成功激活了部分功能。

与此同时，艾普西龙特工 查看了监控录像，发现了开门的密码：2 ，10 ，和 14 。你只需要输入这些数字 就可以获得自由。

但还有一个问题。控制面板只有三个按键，一个是给显示屏上的数字加 5 ，另一个是加 7 ，最后一个则是开平方。

你需要让显示器按顺序出现2 ，10 ，14 这三个数字。

在两个目标数字之间 可以出现其他数字，但是无法重置输入过程，因此，一旦你得到了 2，你需要在此基础上继续输入 直到得到 10 和 14 。

Not only that, Agent Delta explains that there are other traps built into the panel.

If it ever shows the same number more than once, a number greater than 60, or a non-whole number, the room will explode.

Right now, the display reads zero, and time is running out. 

There’s only one way to solve the puzzle, with a few small variations. 

How will you input the code to escape from Dr. Schrödinger’s lair and save the day? 

Pause the video now if you want to figure it out for yourself! 

Answer in: 3 2 1.

德尔塔特工说规则不仅如此，控制面板中还设置了其他陷阱。

如果重复出现了同样的数字，或是数字大于 60，再或者出现了非整数，这个房间就都会爆炸。

现在，显示屏上的数字是 0 而时间所剩无几。

这道题目的解答方法 只有一种且变化很少。

为了逃离薛定谔博士的实验室 并拯救城市，你将如何输入密码？

如果你想自己解题，请在此暂停。

离答案揭晓还有：3 秒，2 秒，1 秒。

You look over your options.

Adding 5 or 7 increases the number, and the square root button will make it smaller.

But there are only a few options where you can use that button: 4 9 16 25, 36, and 49. 

You’d love to make 4 or 16. 

Then you could hit the square root button once or twice to get 2. 

But you can’t make either with just the 5 and 7 buttons. 

What will you do? 

You look at the other possible options for numbers you could take the square root of.

Nine you can’t reach. 

Twenty-five and 49 would take you back to 5 or 7, and you can already get to each of those.

Thirty-six is your only option. 

You add 5, 7, 5, 7, 5, 7, and then hit the square root button.

你思考着对策。

加 5 或加 7 会让数字增加，而平方根会让数字变小。

但使用平方根的机会很少，只有 4，9，16，25，36，49。

你希望能得到 4 或是 16 。

然后开一次或两次根号 就可以得到 2。

但这两个数字都没办法 用加 5 和加 7 获得。

这该如何是好?

你尝试想出其他的对策 得出可以开方的数字。

9 是无法得出的。

25 和 49 会让 你得到 5 和 7 ，但你本来就可以得到这两个数字。

36 成了你唯一的选择。

你先加 5，再加 7，再加 5，再加 7，再加 5，再加 7，然后敲下开平方的按键。

Why that series of 5s and 7s? 

It’s somewhat arbitrary, but you know that you want to avoid 10, 14, and perfect squares, since you’ll need them later. 

This gets you to 6. 

Does that help? 

Looking at your options, you see that 16 is now in your sights. 

You add 5 twice more to reach it. 

Then hit square root twice. 

That gets you to 2. 

You’re on your way! 

Now to 10. 

You can’t get straight there through addition alone, so you’re going to have to reach another square. 

Taking the square root of 9 or 25 would get you to a good place, but it turns out that 25 is unreachable from 2. 

So you add 7 to get to 9, then take the square root again. 

That gets you to 3. Adding 7 again makes 10. 

Finally, you need to reach 14.

为什么以这个顺序加 5 和加 7 呢？

看上去是随机的，但是你需要避开 10，14 和完全平方数，毕竟你之后还要用到它们。

这下你得到了 6。这有用么？

再思考一下，你发现 16 这个数字变得唾手可得。

通过两次加 5 就可以得到。

然后开平方两次。

就得到了 2。

进展不错！

下一个目标数字是 10。

你无法通过加法直接得到这个数字，因此你还是要 先得到某个完全平方数。

对 9 和 25 开根号 会带来不错的结果，但是无法从 2 得到 25 。

所以你在 2 的基础上 加 7 得到 9，然后开根号。

这就得到了 3。再加 7 得到 10。

最后的目标数字是 14。

Thinking backwards, you imagine where you could be before 14: 7 or 9. 

But 9 won’t work because you’ve already used 9. 

However, you could get to 7 by reaching 49 first. 

You add your way towards it, being careful not to hit any of the numbers you’ve hit so far.

You thread your way carefully, adding five 5s and two 7s. 

Then, square root to 7, and add 7 more.

The door opens, and you’re out of the trap.

通过逆向思考，设想在 14 之前 可以得到的数字有哪些？7 或是 9。

但是不能选 9， 因为 9 已经出现过一次。

但是你可以通过 对 49 开根号得到 7。

你通过加法试图得到 49，要小心不重复之前出现过的数字。

你小心翼翼，加上 5 个 5 和 2 个 7。

然后开根号得到 7， 再加 7。

门开了，你们成功脱困。

Thanks to your problem-solving skills, your team gets Schrödinger’s cats out of the box in the nick of time. 

As for Schrödinger, you can be certain of one thing: he’ll be spending quite some time in a box of his own.

由于你出色的问题解决能力，你的小队在最后一刻 抓到了薛定谔的猫。

至于薛定谔，你可以确定的是，他要在自己的盒子里 待上好一段时间了。