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An Asymptotic Expansion

2022-10-07 16:47 作者:Baobhan_Sith  | 我要投稿

马上准备试一下用打字机打一张排版复古的数学小论文,所以把以前一个回答改成英文版,来适配打字机和铅字印刷的排版

In some problems in other fields, we need to obtain the asymptotic expansion of following integral. 

%5Cint_0%5E1%7B%5Cfrac%7B%5Cleft(%201%2Bt%5E2%20%5Cright)%20%5E%7Bx-1%7D%7D%7B1%2Bt%5E%7B2x%7D%7Ddt%7D%0A

Make following substitution

u%3Dt%5E%7Bx%7D%0A

to obtain a new integral

%5Cint_0%5E1%7B%5Cfrac%7B%5Cleft(%201%2Bt%5E2%20%5Cright)%20%5E%7Bx-1%7D%7D%7B1%2Bt%5E%7B2x%7D%7Ddt%7D%3D%5Cfrac%7B1%7D%7Bx%7D%5Cint_0%5E1%7B%5Cfrac%7B%5Cleft(%201%2Bu%5E%7B%5Cfrac%7B2%7D%7Bx%7D%7D%20%5Cright)%20%5E%7Bx-1%7Du%5E%7B%5Cfrac%7B1%7D%7Bx%7D-1%7D%7D%7B1%2Bu%5E2%7Ddu%7D%0A

expand numerator into power series of 1/x

%5Cleft(%201%2Bu%5E%7B%5Cfrac%7B1%7D%7Bx%7D%7D%20%5Cright)%20%5E%7Bx-1%7Du%5E%7B%5Cfrac%7B1%7D%7B2x%7D-1%7D%3D2%5Ex%5Cleft(%20%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B%5Cln%20%5E2u%7D%7B4x%7D%2B%5Cfrac%7B-4%5Cln%20%5E2u%2B%5Cln%20%5E4u%7D%7B16x%5E2%7D%2B%5Cfrac%7B-16%5C!%5C%3A%5Cln%20%5E4u%2B%5Cln%20%5E6u%7D%7B96x%5E3%7D%2BO%5Cleft(%20%5Cfrac%7B1%7D%7Bx%5E4%7D%20%5Cright)%20%5Cright)%20%0A

Then plug expansion into the integral and obtain

%5Cint_0%5E1%7B%5Cfrac%7B%5Cleft(%201%2Bt%5E2%20%5Cright)%20%5E%7Bx-1%7D%7D%7B1%2Bt%5E%7B2x%7D%7Ddt%7D%0A

%3D%5Cfrac%7B2%5Ex%7D%7Bx%7D%5Cleft(%20%5Cfrac%7B%5Cpi%7D%7B8%7D%2B%5Cfrac%7B1%7D%7Bx%7D%5Cfrac%7B%5Cpi%20%5E3%7D%7B64%7D%2B%5Cfrac%7B1%7D%7Bx%5E2%7D%5Cleft(%20-%5Cfrac%7B%5Cpi%20%5E3%7D%7B64%7D%2B%5Cfrac%7B5%5C!%5C%3A%5Cpi%20%5E5%7D%7B1024%7D%20%5Cright)%20%2B%5Cfrac%7B1%7D%7Bx%5E3%7D%5Cleft(%20-%5Cfrac%7B5%5C!%5C%3A%5Cpi%20%5E5%7D%7B384%7D%2B%5Cfrac%7B61%5C!%5C%3A%5Cpi%20%5E7%7D%7B24576%7D%20%5Cright)%20%2BO%5Cleft(%20%5Cfrac%7B1%7D%7Bx%5E4%7D%20%5Cright)%20%5Cright)%20%0A

 

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