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从问题入手的三角换元(2022新高考Ⅱ,12)

2022-12-10 10:57 作者:数学老顽童  | 我要投稿

xy满足x%5E2%2By%5E2-xy%3D1,则(    )

A.x%2By%5Cleqslant%201

B.x%2By%5Cgeqslant%20-2

C.x%5E2%2By%5E2%5Cleqslant%202

D.x%5E2%2By%5E2%5Cgeqslant%201

解:

%5Cbegin%7Balign%7D%0A1%26%3Dx%5E2%2By%5E2-xy%0A%5C%5C%0A%26%3D%5Cleft(%20x%2By%20%5Cright)%20%5E2-3xy%0A%5C%5C%0A%26%5Cgeqslant%20%5Cleft(%20x%2By%20%5Cright)%20%5E2-3%5Ccdot%20%5Cfrac%7B1%7D%7B4%7D%5Cleft(%20x%2By%20%5Cright)%20%5E2%0A%5C%5C%0A%26%3D%5Cfrac%7B1%7D%7B4%7D%5Cleft(%20x%2By%20%5Cright)%20%5E2%0A%5Cend%7Balign%7D

所以x%2By%5Cin%20%5Cleft%5B%20-2%2C2%20%5Cright%5D%20

A错误,B正确;

x%5E2%2By%5E2%3Dr%5E2

三角换元,令x%3Dr%5Ccos%20%20%5Ctheta%20y%3Dr%5Csin%20%20%5Ctheta%20

代入条件中,得r%5E2-r%5Ccos%20%20%5Ctheta%20%5Ccdot%20r%5Csin%20%20%5Ctheta%20%3D1

所以r%5E2%3D%5Cfrac%7B2%7D%7B2-%5Csin%20%202%5Ctheta%7D%5Cin%20%5Cleft%5B%20%5Cfrac%7B2%7D%7B3%7D%2C2%20%5Cright%5D%20

C正确,D错误.

BC.


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