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[Geometry] Inscribed Circle of a Right Triangle

2021-07-02 11:33 作者:AoiSTZ23  | 我要投稿

By: Tao Steven Zheng (郑涛)

【Problem】

 Jiuzhang Suanshu (Gougu 16)

Suppose there is a right triangle whose gou (shorter leg) is 8 bu, and gu (longer leg) is 15 bu. What is the diameter of the inscribed circle?

 

【Solution】

Let a%2Cb%2Cc be the side lengths of the right triangle, where c is the hypotenuse. Let r be the radius and d be the diameter of the inscribed circle. Dissect the right triangle into 6 pieces (Figure 1): 2 red triangles, 2 blue triangles, and 2 yellow triangles.

Figure 1


 

Figure 2


Copy each rectangle four times (Figure 2 top), then combine each pair of triangles of the same color to form rectangles (the yellow triangles form a square). Assemble them to form one large rectangle (Figure 2 bottom). Use this large rectangle to derive three different formulas for calculating the diameter of the inscribed circle.

Formula 1

The area of a large rectangle is equal to the area of four right triangles:

d(a%2Bb%2Bc)%3D4%C3%97%5Cfrac%7B1%7D%7B2%7D%20ab

d(a%2Bb%2Bc)%3D2ab

d%3D%5Cfrac%7B2ab%7D%7Ba%2Bb%2Bc%7D

Formula 2

It can be seen immediately from (Figure 2 bottom) that:

c%3D(a-r)%2B(b-r)

c%2B2r%3Da%2Bb

c%2Bd%3Da%2Bb

d%3Da%2Bb-c

It is known that a%3D8 and b%3D15 , thus

c%3D%5Csqrt%7B8%5E2%2B15%5E2%7D%20%3D17


Formula 1

d%3D%5Cfrac%7B2%C3%978%C3%9715%7D%7B8%2B15%2B17%7D%3D6

Formula 2

d%3D8%2B15-17%3D6

Therefore, the diameter of the inscribed circle is 6 bu.


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